What is the derivative of 1/x-1 ?

The derivative of 1/x-1 is -1/(x^2)

What is the first derivative of 1/x-1 ?

The first derivative of 1/x-1 is -1/(x^2)

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\frac{d}{d x} (\frac{1}{x} - 1)

- \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{x} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{x}) - \frac{d}{d x} (1)

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

\frac{d}{d x} (1) = 0

= - \frac{1}{x ^{2}} - 0

Simplify

= - \frac{1}{x ^{2}}

\int \frac{1}{( 1 + u ^{2} )} d u

\int 30 (x + 2) (x + 3)^{4} d x

f (x) = x^{4} - 3 x^{3} - 9 x^{2} + 5 x

\int_{0}^{\frac{π}{2}} (sin (x)) d x

y^{^{''}} - 7 y^{^{'}} + 12 y = - 2 cos (3 t)

What is the derivative of 1/x-1 ?
The derivative of 1/x-1 is -1/(x^2)
What is the first derivative of 1/x-1 ?
The first derivative of 1/x-1 is -1/(x^2)