What is the derivative of f(x)=3x^2+2ln(8)(x) ?

The derivative of f(x)=3x^2+2ln(8)(x) is 6x+6ln(2)

What is the first derivative of f(x)=3x^2+2ln(8)(x) ?

The first derivative of f(x)=3x^2+2ln(8)(x) is 6x+6ln(2)

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derivative of

f (x) = 3 x^{2} + 2 ln (8) (x)

6 x + 6 ln (2)

Solution steps

\frac{d}{d x} (3 x^{2} + 2 ln (8) x)

Simplify

3 x^{2} + 2 ln (8) x : 3 x^{2} + 6 ln (2) x

= \frac{d}{d x} (3 x^{2} + 6 ln (2) x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (6 ln (2) x)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (6 ln (2) x) = 6 ln (2)

= 6 x + 6 ln (2)

y^{^{'}} = \frac{( x ^{5} )}{y}

\int_{0}^{3 π} 3 x^{2} sin (\frac{1}{6} x) d x

x \to 1 lim (5 x + 1)

x \to 0 lim ((x)^{- 1 + x})

y^{^{''}} - 4 y^{^{'}} + 9 y = 0

What is the derivative of f(x)=3x^2+2ln(8)(x) ?
The derivative of f(x)=3x^2+2ln(8)(x) is 6x+6ln(2)
What is the first derivative of f(x)=3x^2+2ln(8)(x) ?
The first derivative of f(x)=3x^2+2ln(8)(x) is 6x+6ln(2)