What is the slope of y=x^3-9x,(1,-8) ?

The slope of y=x^3-9x,(1,-8) is -6

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slope of y=x^3-9x,(1,-8)

slope

y = x^{3} - 9 x, (1, - 8)

- 6

Solution steps

y = x^{3} - 9 x

In order to find the slope of the function, take the derivative of

x^{3} - 9 x

\frac{d}{d x} (x^{3} - 9 x) = 3 x^{2} - 9

3 x^{2} - 9

Find the value of

3 x^{2} - 9

for

x = 1 : - 6

- 6

\int_{0}^{1} (x^{2} + 1) e^{2 x} d x

6 x^{2} - 4 x y + 4 y^{2} - 14 = 0, (1, 2)

y = x + 1, (8, 3)

f (x) = x^{4} - 2 x^{3} + x - 1

\frac{d}{d t} (e^{r (t) t})