What is the solution for (dy)/(dx)=y(1-0.0002y) ?

The solution for (dy)/(dx)=y(1-0.0002y) is y=-(e^{x+c_{1}})/(1-0.0002e^{x+c_{1)}}

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(dy)/(dx)=y(1-0.0002y)

\frac{d y}{d x} = y (1 - 0.0002 y)

y = - \frac{e ^{x + c_{1}}}{1 - 0.0002 e ^{x + c_{1}}}

Solution steps

\frac{d y}{d x} = y (1 - 0.0002 y)

Solve separable ODE:

y = - \frac{e ^{x + c_{1}}}{1 - 0.0002 e ^{x + c_{1}}}

y = - \frac{e ^{x + c_{1}}}{1 - 0.0002 e ^{x + c_{1}}}

ln (x^{2} + 4)

x \to 0 lim (2 f (x) - 1)

y^{^{''}} + 16 y = 4 t^{2}

\int \frac{x ^{4} + 9}{x ^{2} + 9 x ^{2}} d x

x \to 0 lim ((1 + 2 x)^{- \frac{3}{x}})

What is the solution for (dy)/(dx)=y(1-0.0002y) ?
The solution for (dy)/(dx)=y(1-0.0002y) is y=-(e^{x+c_{1}})/(1-0.0002e^{x+c_{1)}}