What is the tangent of f(x)=7x^4+5x-3,(1,9) ?

The tangent of f(x)=7x^4+5x-3,(1,9) is y=33x-24

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tangent of f(x)=7x^4+5x-3,(1,9)

tangent of

f (x) = 7 x^{4} + 5 x - 3, (1, 9)

y = 33 x - 24

Solution steps

Find the slope of

f (x) = 7 x^{4} + 5 x - 3 : \frac{df ( x )}{d x} = 28 x^{3} + 5

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 33

Find the line with slope m=

33

and passing through

(1, 9) : y = 33 x - 24

y = 33 x - 24

y^{^{'}} = (x + y + 2)^{2}

\frac{d}{d x} (2 x^{2} + 3 x + 4)

\frac{d y}{d x} = sin (y) cos (x)

f (x) = x^{2} + 7, (4, 23)

\int 2 y + 4 e^{y} d y

What is the tangent of f(x)=7x^4+5x-3,(1,9) ?
The tangent of f(x)=7x^4+5x-3,(1,9) is y=33x-24