What is (\partial)/(\partial x)(x^2+xy) ?

The answer to (\partial)/(\partial x)(x^2+xy) is 2x+y

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(\partial)/(\partial x)(x^2+xy)

\frac{\partial}{\partial x} (x^{2} + x y)

2 x + y

Solution steps

\frac{\partial}{\partial x} (x^{2} + x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (x y) = y

= 2 x + y

f (x) = 7 x^{4} + 5 x - 3, (1, 9)

y^{^{'}} = (x + y + 2)^{2}

\frac{d}{d x} (2 x^{2} + 3 x + 4)

\frac{d y}{d x} = sin (y) cos (x)

f (x) = x^{2} + 7, (4, 23)

What is (\partial)/(\partial x)(x^2+xy) ?
The answer to (\partial)/(\partial x)(x^2+xy) is 2x+y