What is the integral of 8u^{9/8} ?

The integral of 8u^{9/8} is 64/17 u^{17/8}+C

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integral of 8u^{9/8}

\int 8 u^{\frac{9}{8}} d u

\frac{64}{17} u^{\frac{17}{8}} + C

Solution steps

\int 8 u^{\frac{9}{8}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int u^{\frac{9}{8}} d u

Apply the Power Rule

: \frac{8}{17} u^{\frac{17}{8}}

= 8 \cdot \frac{8}{17} u^{\frac{17}{8}}

Simplify

8 \cdot \frac{8}{17} u^{\frac{17}{8}} : \frac{64}{17} u^{\frac{17}{8}}

= \frac{64}{17} u^{\frac{17}{8}}

Add a constant to the solution

= \frac{64}{17} u^{\frac{17}{8}} + C

x = y^{2} - 2, (- 2, 2)

y^{'} = y (1 - 0.0008 y)

f (x) = \frac{2 x}{x - 1}

\int sin (x) \cdot cos^{2} (x) d x

\frac{d}{d x} (e^{4 x^{2 + 1}})