What is laplacetransform-4sin(4t) ?

The answer to laplacetransform-4sin(4t) is -(16)/(s^2+16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform-4sin(4t)

laplace transform

- 4 sin (4 t)

- \frac{16}{s ^{2} + 16}

Solution steps

L {- 4 sin (4 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 4 L {sin (4 t)}

L {sin (4 t)} : \frac{4}{s ^{2} + 16}

= - 4 \cdot \frac{4}{s ^{2} + 16}

Refine

- 4 \frac{4}{s ^{2} + 16} : - \frac{16}{s ^{2} + 16}

= - \frac{16}{s ^{2} + 16}

\frac{6}{( s - 2 ) ^{2} ( s - 4 ) ^{4}}

x \frac{d y}{d x} + 1 = x + y

\frac{\partial}{\partial y} (6 - 3 x - 2 y)

\int_{- \infty}^{- 1} e^{- 34 t} d t

n = 1 \sum \infty \frac{2 n}{1 + n ^{4}}

What is laplacetransform-4sin(4t) ?
The answer to laplacetransform-4sin(4t) is -(16)/(s^2+16)