What is (\partial)/(\partial x)((e^{x-y})goog) ?

The answer to (\partial)/(\partial x)((e^{x-y})goog) is g^2e^{x-y}o^2

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(\partial)/(\partial x)((e^{x-y})goog)

\frac{\partial}{\partial x} ((e^{x - y}) g oo g)

g^{2} e^{x - y} o^{2}

Solution steps

\frac{\partial}{\partial x} ((e^{x - y}) g oo g)

Simplify

(e^{x - y}) g oo g : g^{2} e^{x - y} o^{2}

= \frac{\partial}{\partial x} (g^{2} e^{x - y} o^{2})

Treat

g, y, o

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= g^{2} o^{2} \frac{\partial}{\partial x} (e^{x - y})

Apply the chain rule:

e^{x - y} \frac{\partial}{\partial x} (x - y)

= e^{x - y} \frac{\partial}{\partial x} (x - y)

\frac{\partial}{\partial x} (x - y) = 1

= g^{2} o^{2} e^{x - y} \cdot 1

Simplify

= g^{2} e^{x - y} o^{2}

f (x) = 1 - 2 cos (x)

\frac{d}{d x} ((\frac{x - 5}{x + 5})^{4})

\int \frac{x ^{3}}{x ^{2} - x - 2} d x

y = x + x^{π}

f (x) = \frac{1}{4 + 3 x}, at x = 2

What is (\partial)/(\partial x)((e^{x-y})goog) ?
The answer to (\partial)/(\partial x)((e^{x-y})goog) is g^2e^{x-y}o^2