What is the derivative of y=sqrt(x)+x^pi ?

The derivative of y=sqrt(x)+x^pi is 1/(2sqrt(x))+pix^{pi-1}

What is the first derivative of y=sqrt(x)+x^pi ?

The first derivative of y=sqrt(x)+x^pi is 1/(2sqrt(x))+pix^{pi-1}

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derivative of

y = x + x^{π}

\frac{1}{2 x} + π x^{π - 1}

Solution steps

\frac{d}{d x} (x + x^{π})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x) + \frac{d}{d x} (x^{π})

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d}{d x} (x^{π}) = π x^{π - 1}

= \frac{1}{2 x} + π x^{π - 1}

f (x) = \frac{1}{4 + 3 x}, at x = 2

y = - x^{- 1} + \frac{3}{5} x + \frac{1}{2}

\int (t^{2} + 2 t + 1)^{4} (t + 1) d t

\int_{0}^{5} ∣ 9 - 3 t ∣ d t

y = x, y = x^{2}, y = - x + 1

What is the derivative of y=sqrt(x)+x^pi ?
The derivative of y=sqrt(x)+x^pi is 1/(2sqrt(x))+pix^{pi-1}
What is the first derivative of y=sqrt(x)+x^pi ?
The first derivative of y=sqrt(x)+x^pi is 1/(2sqrt(x))+pix^{pi-1}