What is the tangent of f(x)= 1/(4+3x),\at x=2 ?

The tangent of f(x)= 1/(4+3x),\at x=2 is y=-3/100 x+4/25

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tangent of f(x)= 1/(4+3x),\at x=2

tangent of

f (x) = \frac{1}{4 + 3 x}, at x = 2

y = - \frac{3}{100} x + \frac{4}{25}

Solution steps

Find the tangent point:

(2, \frac{1}{10})

Find the slope of

f (x) = \frac{1}{4 + 3 x} : \frac{df ( x )}{d x} = - \frac{3}{( 4 + 3 x ) ^{2}}

Compute the slope of

f (x) = \frac{1}{4 + 3 x}

x = 2 : m = - \frac{3}{100}

Find the line with slope m=

- \frac{3}{100}

and passing through

(2, \frac{1}{10}) : y = - \frac{3}{100} x + \frac{4}{25}

y = - \frac{3}{100} x + \frac{4}{25}

y = - x^{- 1} + \frac{3}{5} x + \frac{1}{2}

\int (t^{2} + 2 t + 1)^{4} (t + 1) d t

\int_{0}^{5} ∣ 9 - 3 t ∣ d t

y = x, y = x^{2}, y = - x + 1

k = 1 \sum \infty k^{k} x^{k}

What is the tangent of f(x)= 1/(4+3x),\at x=2 ?
The tangent of f(x)= 1/(4+3x),\at x=2 is y=-3/100 x+4/25