What is the derivative of f(x)=(2x-3)/(4-x) ?

The derivative of f(x)=(2x-3)/(4-x) is 5/((4-x)^2)

What is the first derivative of f(x)=(2x-3)/(4-x) ?

The first derivative of f(x)=(2x-3)/(4-x) is 5/((4-x)^2)

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derivative of

f (x) = \frac{2 x - 3}{4 - x}

\frac{5}{( 4 - x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2 x - 3}{4 - x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 x - 3 ) ( 4 - x ) - \frac{d}{d x} ( 4 - x ) ( 2 x - 3 )}{( 4 - x ) ^{2}}

\frac{d}{d x} (2 x - 3) = 2

\frac{d}{d x} (4 - x) = - 1

= \frac{2 ( 4 - x ) - ( - 1 ) ( 2 x - 3 )}{( 4 - x ) ^{2}}

Simplify

\frac{2 ( 4 - x ) - ( - 1 ) ( 2 x - 3 )}{( 4 - x ) ^{2}} : \frac{5}{( 4 - x ) ^{2}}

= \frac{5}{( 4 - x ) ^{2}}

\frac{\partial}{\partial x} (\frac{x}{1 + x ^{2}})

y (x + 4) = 1, x = 0, y = 0, x = 4

\int (ln (16 x))^{2} d x

\int (- 6 x^{6} - 2 x^{3} - 4) d x

y = x^{2} - 39, y = 9 - 2 x

What is the derivative of f(x)=(2x-3)/(4-x) ?
The derivative of f(x)=(2x-3)/(4-x) is 5/((4-x)^2)
What is the first derivative of f(x)=(2x-3)/(4-x) ?
The first derivative of f(x)=(2x-3)/(4-x) is 5/((4-x)^2)