What is the solution for y^'-7/(600+2t)y=6 ?

The solution for y^'-7/(600+2t)y=6 is y=-(6(2t+600))/5+c_{1}(600+2t)^{7/2}

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y^'-7/(600+2t)y=6

y^{^{'}} - \frac{7}{600 + 2 t} y = 6

y = - \frac{6 ( 2 t + 600 )}{5} + c_{1} (600 + 2 t)^{\frac{7}{2}}

Solution steps

y^{'} (t) - \frac{7}{600 + 2 t} y = 6

Solve linear ODE:

y = - \frac{6 ( 2 t + 600 )}{5} + c_{1} (600 + 2 t)^{\frac{7}{2}}

y = - \frac{6 ( 2 t + 600 )}{5} + c_{1} (600 + 2 t)^{\frac{7}{2}}

\int_{0}^{2} \frac{1}{x ^{2}} d x

\frac{\partial}{\partial x} (e^{x y} sin (x yz))

t^{2} y^{^{''}} - 7 t y^{^{'}} + 15 y = 0

x \to \infty lim (x ln (x))

\frac{s ^{2}}{s ^{3} - 1}

What is the solution for y^'-7/(600+2t)y=6 ?
The solution for y^'-7/(600+2t)y=6 is y=-(6(2t+600))/5+c_{1}(600+2t)^{7/2}