What is (\partial)/(\partial x)(sin(x)+sin(y)) ?

The answer to (\partial)/(\partial x)(sin(x)+sin(y)) is cos(x)

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(\partial)/(\partial x)(sin(x)+sin(y))

\frac{\partial}{\partial x} (sin (x) + sin (y))

cos (x)

Solution steps

\frac{\partial}{\partial x} (sin (x) + sin (y))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (sin (x)) + \frac{\partial}{\partial x} (sin (y))

\frac{\partial}{\partial x} (sin (x)) = cos (x)

\frac{\partial}{\partial x} (sin (y)) = 0

= cos (x) + 0

Simplify

= cos (x)

\int 4 x + x d x

5 x^{3} + 10 x^{2} - 2 x + 1

x^{2} - 2 x + 1

2 x y + 6 x + (x^{2} - 4) y^{^{'}} = 0

y = (9 x + 5) x^{2}

What is (\partial)/(\partial x)(sin(x)+sin(y)) ?
The answer to (\partial)/(\partial x)(sin(x)+sin(y)) is cos(x)