What is the integral from 0 to 1 of 1/(x^2) ?

The integral from 0 to 1 of 1/(x^2) is diverges

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integral from 0 to 1 of 1/(x^2)

\int_{0}^{1} \frac{1}{x ^{2}} d x

diverges

Solution steps

\int_{0}^{1} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{0}^{1}

= [- \frac{1}{x}]_{0}^{1}

Compute the boundaries:

diverges

= diverges

\int \frac{tan ^{2} ( x )}{sec ^{2} ( x )} d x

\int \frac{2 x + 1}{x - 2} d x

y^{^{'}} = y (y^{3} - 1)

\int (e^{- x} - e^{5}) \cdot (e^{x} + e^{- 2}) d x

y^{^{'}} - y = 10 t e^{2 t}, y (0) = 1

What is the integral from 0 to 1 of 1/(x^2) ?
The integral from 0 to 1 of 1/(x^2) is diverges