What is the derivative of (2x+3^3) ?

The derivative of (2x+3^3) is 6(2x+3)^2

What is the first derivative of (2x+3^3) ?

The first derivative of (2x+3^3) is 6(2x+3)^2

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\frac{d}{d x} ((2 x + 3)^{3})

6 (2 x + 3)^{2}

Solution steps

\frac{d}{d x} ((2 x + 3)^{3})

Apply the chain rule:

3 (2 x + 3)^{2} \frac{d}{d x} (2 x + 3)

= 3 (2 x + 3)^{2} \frac{d}{d x} (2 x + 3)

\frac{d}{d x} (2 x + 3) = 2

= 3 (2 x + 3)^{2} \cdot 2

Simplify

= 6 (2 x + 3)^{2}

f (x) = \frac{x}{x + 3}, at x = - 5

9 x^{2} \cdot cos (x) \cdot cot (x)

\frac{\partial}{\partial x} (r (θ, x) sin (θ))

x = 5, y = 5 x

\frac{sin ( 5 x )}{3 x}

What is the derivative of (2x+3^3) ?
The derivative of (2x+3^3) is 6(2x+3)^2
What is the first derivative of (2x+3^3) ?
The first derivative of (2x+3^3) is 6(2x+3)^2