What is the integral from 2 to infinity of xe^{-3x} ?

The integral from 2 to infinity of xe^{-3x} is 7/(9e^6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 2 to infinity of xe^{-3x}

\int_{2}^{\infty} x e^{- 3 x} d x

\frac{7}{9 e ^{6}}

Decimal

0.00192 \dots

Solution steps

\int_{2}^{\infty} x e^{- 3 x} d x

Compute the indefinite integral:

\int x e^{- 3 x} d x = \frac{1}{9} (- 3 e^{- 3 x} x - e^{- 3 x}) + C

Compute the boundaries:

\int_{2}^{\infty} x e^{- 3 x} d x = 0 - (- \frac{7}{9 e ^{6}})

= 0 - (- \frac{7}{9 e ^{6}})

Simplify

= \frac{7}{9 e ^{6}}

\frac{d}{d t} (5 t^{2} x)

\int u^{4} d u

x \to 0 - lim (\frac{x ^{2}}{3} - \frac{1}{x})

y^{^{'''}} + 6 y^{^{''}} + 45 y^{^{'}} = 0

y - x + x y^{^{'}} = 0

What is the integral from 2 to infinity of xe^{-3x} ?
The integral from 2 to infinity of xe^{-3x} is 7/(9e^6)