What is the solution for y^{'''}+6y^{''}+45y^'=0 ?

The solution for y^{'''}+6y^{''}+45y^'=0 is y=c_{1}+e^{-3t}(c_{2}cos(6t)+c_{3}sin(6t))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{'''}+6y^{''}+45y^'=0

y^{^{'''}} + 6 y^{^{''}} + 45 y^{^{'}} = 0

y = c_{1} + e^{- 3 t} (c_{2} cos (6 t) + c_{3} sin (6 t))

Solution steps

y^{'''} (t) + 6 y^{''} (t) + 45 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + e^{- 3 t} (c_{2} cos (6 t) + c_{3} sin (6 t))

y = c_{1} + e^{- 3 t} (c_{2} cos (6 t) + c_{3} sin (6 t))

y - x + x y^{^{'}} = 0

\int_{3}^{x^{3}} t^{4} d t

\int_{0}^{2} 2 x - x^{2} d x

\frac{\partial}{\partial y} (\frac{( 2 x + y )}{z})

f (x) = \frac{4}{x}, (4, 2)

What is the solution for y^{'''}+6y^{''}+45y^'=0 ?
The solution for y^{'''}+6y^{''}+45y^'=0 is y=c_{1}+e^{-3t}(c_{2}cos(6t)+c_{3}sin(6t))