What is the solution for xydx+y^2dy=0 ?

The solution for xydx+y^2dy=0 is y=sqrt(-x^2+c_{1)},y=-sqrt(-x^2+c_{1)}

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xydx+y^2dy=0

x y d x + y^{2} d y = 0

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

Solution steps

x y d x + y^{2} d y = 0

Solve separable ODE:

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

f (x) = x^{3} - 4 x + 6

\frac{d}{d x} (\frac{x ^{2}}{1 + e ^{x}})

\int \frac{10 x ^{2}}{x ^{4} - 1} d x

n = 5 \sum \infty (\frac{4}{5})^{n}

\int 4 x^{3} (4 + x^{4})^{\frac{1}{3}} d x

What is the solution for xydx+y^2dy=0 ?
The solution for xydx+y^2dy=0 is y=sqrt(-x^2+c_{1)},y=-sqrt(-x^2+c_{1)}