What is the tangent of 2xsqrt(x),\at x=1 ?

The tangent of 2xsqrt(x),\at x=1 is y=3x-1

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tangent of 2xsqrt(x),\at x=1

tangent of

2 x x, at x = 1

y = 3 x - 1

Solution steps

Find the tangent point:

(1, 2)

Find the slope of

y = 2 x x : \frac{d y}{d x} = 3 x

Compute the slope of

y = 2 x x

x = 1 : m = 3

Find the line with slope m=

3

and passing through

(1, 2) : y = 3 x - 1

y = 3 x - 1

6 x

\int (2 x y - tan (y)) d x

\frac{d}{d x} (9 e^{- x} + e^{2 x})

y = cos (x), y = 2 - cos (x)

\frac{d}{d x} (3 x + 2)

What is the tangent of 2xsqrt(x),\at x=1 ?
The tangent of 2xsqrt(x),\at x=1 is y=3x-1