What is the tangent of f(x)=sqrt(7x+1),\at x=5 ?

The tangent of f(x)=sqrt(7x+1),\at x=5 is y= 7/12 x+37/12

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tangent of f(x)=sqrt(7x+1),\at x=5

tangent of

f (x) = 7 x + 1, at x = 5

y = \frac{7}{12} x + \frac{37}{12}

Solution steps

Find the tangent point:

(5, 6)

Find the slope of

f (x) = 7 x + 1 : \frac{df ( x )}{d x} = \frac{7}{2 7 x + 1}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{7}{12}

Find the line with slope m=

\frac{7}{12}

and passing through

(5, 6) : y = \frac{7}{12} x + \frac{37}{12}

y = \frac{7}{12} x + \frac{37}{12}

2 sin (2 x - π), 5 sin (2 x - 3 π)

\int \frac{1}{( 5 + x ) ^{2}} d x

\frac{d}{d x} (\frac{x ^{2}}{( x - 1 )})

\int x^{2} + 6 e^{x} + C d x

\int e x d x

What is the tangent of f(x)=sqrt(7x+1),\at x=5 ?
The tangent of f(x)=sqrt(7x+1),\at x=5 is y= 7/12 x+37/12