What is the derivative of (4x+3^2) ?

The derivative of (4x+3^2) is 8(4x+3)

What is the first derivative of (4x+3^2) ?

The first derivative of (4x+3^2) is 8(4x+3)

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\frac{d}{d x} ((4 x + 3)^{2})

8 (4 x + 3)

Solution steps

\frac{d}{d x} ((4 x + 3)^{2})

Apply the chain rule:

2 (4 x + 3) \frac{d}{d x} (4 x + 3)

= 2 (4 x + 3) \frac{d}{d x} (4 x + 3)

\frac{d}{d x} (4 x + 3) = 4

= 2 (4 x + 3) \cdot 4

Simplify

= 8 (4 x + 3)

\int_{0}^{2} (2 - x) x d x

\frac{\partial}{\partial x} (e^{2 x yz - 1})

\frac{d}{d x} (e^{2 x} + 4)

\int_{0}^{4} (x + 3 x) d x

\int e^{x} e^{x} + 5 d x

What is the derivative of (4x+3^2) ?
The derivative of (4x+3^2) is 8(4x+3)
What is the first derivative of (4x+3^2) ?
The first derivative of (4x+3^2) is 8(4x+3)