What is the derivative of 1+sin(2x) ?

The derivative of 1+sin(2x) is 2cos(2x)

What is the first derivative of 1+sin(2x) ?

The first derivative of 1+sin(2x) is 2cos(2x)

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\frac{d}{d x} (1 + sin (2 x))

2 cos (2 x)

Solution steps

\frac{d}{d x} (1 + sin (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (sin (2 x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (sin (2 x)) = cos (2 x) \cdot 2

= 0 + cos (2 x) \cdot 2

Simplify

= 2 cos (2 x)

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\int_{- \infty}^{0} e^{9 x} d x

What is the derivative of 1+sin(2x) ?
The derivative of 1+sin(2x) is 2cos(2x)
What is the first derivative of 1+sin(2x) ?
The first derivative of 1+sin(2x) is 2cos(2x)