What is implicit (dy)/(dx),xe^y-10x+3y=0 ?

The answer to implicit (dy)/(dx),xe^y-10x+3y=0 is (dy)/(dx)=(-e^y+10)/(e^yx+3)

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implicit (dy)/(dx),xe^y-10x+3y=0

implicit derivative

\frac{d y}{d x}, x e^{y} - 10 x + 3 y = 0

\frac{d y}{d x} = \frac{- e ^{y} + 10}{e ^{y} x + 3}

Solution steps

x e^{y} - 10 x + 3 y = 0

Treat

y

y (x)

Differentiate both sides:

e^{y} + e^{y} x \frac{d y}{d x} - 10 + 3 \frac{d y}{d x} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{- e ^{y} + 10}{e ^{y} x + 3}

\frac{d y}{d x} = \frac{- e ^{y} + 10}{e ^{y} x + 3}

(sin (3 x))^{l n (x)}

\frac{\partial}{\partial x} (2 x + y^{2})

\frac{d}{d x} (arcsinh (tan (x)))

\frac{d}{d x} (8 + 3 x^{2})

\int ln (9 x + 4) d x

What is implicit (dy)/(dx),xe^y-10x+3y=0 ?
The answer to implicit (dy)/(dx),xe^y-10x+3y=0 is (dy)/(dx)=(-e^y+10)/(e^yx+3)