What is the limit as t approaches 0 of cos(t) ?

The limit as t approaches 0 of cos(t) is 1

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limit as t approaches 0 of cos(t)

t \to 0 lim (cos (t))

1

Solution steps

t \to 0 lim (cos (t))

Plug in the value

t = 0

= cos (0)

Use the following trivial identity:

cos (0) = 1

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 1

\int - cos (x) + sin (x) + 1 d x

n = 2 \sum \infty 5 (- \frac{1}{3})^{n}

\int \frac{5 x ^{2}}{2} d x

y = \frac{3 ln ( 4 x )}{5 - 2 x}

f (x) = - 3 x^{3} - 2 x, (- 1, 5)

What is the limit as t approaches 0 of cos(t) ?
The limit as t approaches 0 of cos(t) is 1