What is the derivative of-2x^2-4x+1 ?

The derivative of-2x^2-4x+1 is -4x-4

What is the first derivative of-2x^2-4x+1 ?

The first derivative of-2x^2-4x+1 is -4x-4

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derivative of

- 2 x^{2} - 4 x + 1

- 4 x - 4

Solution steps

\frac{d}{d x} (- 2 x^{2} - 4 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (1) = 0

= - 4 x - 4 + 0

Simplify

= - 4 x - 4

(\frac{10}{x})^{^{'}}

x \to 8 - lim (\frac{x - 8}{x - 8})

x \to 12 lim (\frac{x - 12}{x ^{2} - 144})

\frac{s}{s ^{2} + 8 s + 25}

y = \frac{2 x + 3}{3 x - 2}, (1, 5)

What is the derivative of-2x^2-4x+1 ?
The derivative of-2x^2-4x+1 is -4x-4
What is the first derivative of-2x^2-4x+1 ?
The first derivative of-2x^2-4x+1 is -4x-4