Solution
Solution
Solution steps
Apply the chain rule:
Simplify
Popular Examples
(x^2+y^2)dx+(2xy)dy=0y^'=(x^2-y^2)/(xy),y(2)=5(\partial)/(\partial y)(e^{xyz^4}yz^4)(\partial)/(\partial y)(x^2-2xy+2y^2)tangent of f(x)=x^3-4x,(2,0)tangent of
Frequently Asked Questions (FAQ)
What is the derivative of (x-1^{2/3}) ?
The derivative of (x-1^{2/3}) is 2/(3(x-1)^{1/3)}What is the first derivative of (x-1^{2/3}) ?
The first derivative of (x-1^{2/3}) is 2/(3(x-1)^{1/3)}