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Popular >

area y^2=4+x,y^2+x=2

Solution

area

y^{2} = 4 + x, y^{2} + x = 2

Solution

No Solution

Solution steps

Isolate

y

for

y^{2} = 4 + x : y = 4 + x, y = - 4 + x

Isolate

y

for

y^{2} + x = 2 : y = 2 - x, y = - 2 - x

f_{1} (x) = 4 + x

f_{2} (x) = - 4 + x

To find the intersection points solve

f_{i} (x) = f_{j} (x)

4 + x = - 4 + x : x = - 4

4 + x = 2 - x : x = - 1

4 + x = - 2 - x :

No Solution for

x \in R

- 4 + x = 2 - x :

No Solution for

x \in R

- 4 + x = - 2 - x : x = - 1

2 - x = - 2 - x : x = 2

Curves not bounded

= No Solution

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Frequently Asked Questions (FAQ)

What is area y^2=4+x,y^2+x=2 ?
The answer to area y^2=4+x,y^2+x=2 is No Solution