What is the derivative of \sqrt[3]{x-5} ?

The derivative of \sqrt[3]{x-5} is 1/(3(x-5)^{2/3)}

What is the first derivative of \sqrt[3]{x-5} ?

The first derivative of \sqrt[3]{x-5} is 1/(3(x-5)^{2/3)}

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derivative of

\frac{1}{3 ( x - 5 ) ^{\frac{2}{3}}}

Solution steps

Apply the chain rule:

\frac{1}{3 ( x - 5 ) ^{\frac{2}{3}}} \frac{d}{d x} (x - 5)

= \frac{1}{3 ( x - 5 ) ^{\frac{2}{3}}} \frac{d}{d x} (x - 5)

\frac{d}{d x} (x - 5) = 1

= \frac{1}{3 ( x - 5 ) ^{\frac{2}{3}}} \cdot 1

Simplify

= \frac{1}{3 ( x - 5 ) ^{\frac{2}{3}}}

\frac{1 - 3 t}{5 + t}

y^{^{''}} - 10 y^{^{'}} + 24 y = 0

(r (θ) cos (θ))^{^{'}}

\int \frac{1}{2 u} d u

f (x) = e x

What is the derivative of \sqrt[3]{x-5} ?
The derivative of \sqrt[3]{x-5} is 1/(3(x-5)^{2/3)}
What is the first derivative of \sqrt[3]{x-5} ?
The first derivative of \sqrt[3]{x-5} is 1/(3(x-5)^{2/3)}