What is the derivative of sin(3x+cos(2x)) ?

The derivative of sin(3x+cos(2x)) is cos(3x)*3-sin(2x)*2

What is the first derivative of sin(3x+cos(2x)) ?

The first derivative of sin(3x+cos(2x)) is cos(3x)*3-sin(2x)*2

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\frac{d}{d x} (sin (3 x) + cos (2 x))

cos (3 x) \cdot 3 - sin (2 x) \cdot 2

Solution steps

\frac{d}{d x} (sin (3 x) + cos (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin (3 x)) + \frac{d}{d x} (cos (2 x))

\frac{d}{d x} (sin (3 x)) = cos (3 x) \cdot 3

\frac{d}{d x} (cos (2 x)) = - sin (2 x) \cdot 2

= cos (3 x) \cdot 3 - sin (2 x) \cdot 2

\int_{0}^{1} \frac{2 x ^{2}}{1 + x ^{2}} d x

1 - x^{2}

x \to 0 lim (x^{6} cos (\frac{3}{x}))

\frac{d Q}{d t} = - \frac{5}{980 - \frac{3 t}{10}} Q + 14.1

\int_{4}^{5} \frac{1}{x} d x

What is the derivative of sin(3x+cos(2x)) ?
The derivative of sin(3x+cos(2x)) is cos(3x)*3-sin(2x)*2
What is the first derivative of sin(3x+cos(2x)) ?
The first derivative of sin(3x+cos(2x)) is cos(3x)*3-sin(2x)*2