What is the tangent of g(x)=2x^2 ?

The tangent of g(x)=2x^2 is y=4a_{0}x-2a_{0}^2

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tangent of g(x)=2x^2

tangent of

g (x) = 2 x^{2}

y = 4 a_{0} x - 2 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 2 a_{0}^{2})

Find the slope of

g (x) = 2 x^{2} : \frac{d g ( x )}{d x} = 4 x

Compute the slope of

g (x) = 2 x^{2}

x = a_{0} : m = 4 a_{0}

Find the line with slope m=

4 a_{0}

and passing through

(a_{0}, 2 a_{0}^{2}) : y = 4 a_{0} x - 2 a_{0}^{2}

y = 4 a_{0} x - 2 a_{0}^{2}

h \to 0 lim (\frac{cos ( h )}{h})

\int \frac{3 x}{9 + x ^{2}} d x

f (x) = 2^{2 x}

\int_{1}^{5} 2 r^{2} ln (r) d r

\frac{d}{d x} (ln (x^{2} + 4 x))

What is the tangent of g(x)=2x^2 ?
The tangent of g(x)=2x^2 is y=4a_{0}x-2a_{0}^2