What is the integral of 24xe^{2.4x} ?

The integral of 24xe^{2.4x} is 24(0.41666…e^{2.4x}x-0.17361…e^{2.4x})+C

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integral of 24xe^{2.4x}

\int 24 x e^{2.4 x} d x

24 (0.41666 \dots e^{2.4 x} x - 0.17361 \dots e^{2.4 x}) + C

Solution steps

\int 24 x e^{2.4 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 24 \cdot \int x e^{2.4 x} d x

Apply Integration By Parts

: 0.41666 \dots e^{2.4 x} x - \int 0.41666 \dots e^{2.4 x} d x

= 24 (0.41666 \dots e^{2.4 x} x - \int 0.41666 \dots e^{2.4 x} d x)

\int 0.41666 \dots e^{2.4 x} d x = 0.17361 \dots e^{2.4 x}

= 24 (0.41666 \dots e^{2.4 x} x - 0.17361 \dots e^{2.4 x})

Add a constant to the solution

= 24 (0.41666 \dots e^{2.4 x} x - 0.17361 \dots e^{2.4 x}) + C

\frac{d}{d x} (x + 2 x)

\frac{\partial}{\partial x} (x e^{- x^{2}})

y = sec (x) - 2 cos (x), (\frac{π}{3}, 1)

n = 0 \sum \infty (0.7)^{n}

\frac{sec ( y )}{y ^{8}}

What is the integral of 24xe^{2.4x} ?
The integral of 24xe^{2.4x} is 24(0.41666…e^{2.4x}x-0.17361…e^{2.4x})+C