What is the d/(dt)(2arctan(t)) ?

The d/(dt)(2arctan(t)) is 2/(t^2+1)

What is the first d/(dt)(2arctan(t)) ?

The first d/(dt)(2arctan(t)) is 2/(t^2+1)

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\frac{d}{d t} (2 arctan (t))

\frac{2}{t ^{2} + 1}

Solution steps

\frac{d}{d t} (2 arctan (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (arctan (t))

Apply the common derivative:

\frac{d}{d t} (arctan (t)) = \frac{1}{t ^{2} + 1}

= 2 \cdot \frac{1}{t ^{2} + 1}

Simplify

2 \cdot \frac{1}{t ^{2} + 1} : \frac{2}{t ^{2} + 1}

= \frac{2}{t ^{2} + 1}

x^{^{'}} = x^{2} e^{- 2 t}

\int_{0}^{1} (x - e^{x})^{2} d x

\int \frac{1}{( t + 1 ) ^{2}} d t

\int_{0}^{1} \frac{3}{1 - x ^{2}} d x

f (x) = 3 x + 3 x

What is the d/(dt)(2arctan(t)) ?
The d/(dt)(2arctan(t)) is 2/(t^2+1)
What is the first d/(dt)(2arctan(t)) ?
The first d/(dt)(2arctan(t)) is 2/(t^2+1)