What is the solution for (2x-y)dx+(2y-x)dy=0 ?

The solution for (2x-y)dx+(2y-x)dy=0 is y=(x+sqrt(-3x^2+c_{1)})/2 ,y=(x-sqrt(-3x^2+c_{1)})/2

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(2x-y)dx+(2y-x)dy=0

(2 x - y) d x + (2 y - x) d y = 0

y = \frac{x + - 3 x ^{2} + c _{1}}{2}, y = \frac{x - - 3 x ^{2} + c _{1}}{2}

Solution steps

(2 x - y) d x + (2 y - x) d y = 0

Solve exact ODE:

y = \frac{x + - 3 x ^{2} + c _{1}}{2}, y = \frac{x - - 3 x ^{2} + c _{1}}{2}

y = \frac{x + - 3 x ^{2} + c _{1}}{2}, y = \frac{x - - 3 x ^{2} + c _{1}}{2}

\frac{d}{d x} ((1 - x)^{- 2})

y^{^{'}} = \frac{y}{x} + 1

y^{^{'''}} + 2 y^{^{''}} - 5 y^{^{'}} - 6 y = 0

\int_{0}^{π} 16 sin (x) d x

y^{^{''}} - y^{^{'}} + 20 y = 0

What is the solution for (2x-y)dx+(2y-x)dy=0 ?
The solution for (2x-y)dx+(2y-x)dy=0 is y=(x+sqrt(-3x^2+c_{1)})/2 ,y=(x-sqrt(-3x^2+c_{1)})/2