What is area y=x^3,y=x^2-2x,[-1,1] ?

The answer to area y=x^3,y=x^2-2x,[-1,1] is 5/2

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area y=x^3,y=x^2-2x,[-1,1]

area

y = x^{3}, y = x^{2} - 2 x, [- 1, 1]

\frac{5}{2}

Decimal Notation

2.5

Solution steps

Apply the area formula:

\int_{- 1}^{1} x^{3} - (x^{2} - 2 x) d x

Solve

\int_{- 1}^{1} x^{3} - (x^{2} - 2 x) d x : \frac{5}{2}

The area is:

= \frac{5}{2}

\frac{2}{3} x^{3} + x^{2} - 12 x + 12

f (t) = t

y^{^{'}} = e^{5 x + 4 y}

n = 0 \sum \infty \frac{1}{5}

y = 3 x^{2} + 3 x - 5

What is area y=x^3,y=x^2-2x,[-1,1] ?
The answer to area y=x^3,y=x^2-2x,[-1,1] is 5/2