What is the solution for (1+x^2)y^{''}=-2xy^' ?

The solution for (1+x^2)y^{''}=-2xy^' is y=c_{1}arctan(x)+c_{2}

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(1+x^2)y^{''}=-2xy^'

(1 + x^{2}) y^{^{''}} = - 2 x y^{^{'}}

y = c_{1} arctan (x) + c_{2}

Solution steps

(1 + x^{2}) y^{''} (x) = - 2 x y^{'} (x)

Solve using substitution:

y = c_{1} arctan (x) + c_{2}

y = c_{1} arctan (x) + c_{2}

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What is the solution for (1+x^2)y^{''}=-2xy^' ?
The solution for (1+x^2)y^{''}=-2xy^' is y=c_{1}arctan(x)+c_{2}