What is the sum from n=8 to infinity of e^{3-4n} ?

The sum from n=8 to infinity of e^{3-4n} is converges

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sum from n=8 to infinity of e^{3-4n}

n = 8 \sum \infty e^{3 - 4 n}

converges

Solution steps

n = 8 \sum \infty e^{3 - 4 n}

Apply Series Ratio Test:

converges

= converges

\int \frac{1}{2 x ^{3}} d x

\frac{\partial}{\partial x} (x^{2} y^{2})

\frac{\partial}{\partial x} (cos (sin (x^{2})))

\frac{d}{d v} (ln (cosh (2 v)) - \frac{1}{2} tanh^{2} (2 v))

\frac{10}{s ( s + 1 )}

What is the sum from n=8 to infinity of e^{3-4n} ?
The sum from n=8 to infinity of e^{3-4n} is converges