What is the integral of 1/(4y) ?

The integral of 1/(4y) is 1/4 ln|y|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(4y)

\int \frac{1}{4 y} d y

\frac{1}{4} ln ∣ y ∣ + C

Solution steps

\int \frac{1}{4 y} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int \frac{1}{y} d y

Use the common integral:

\int \frac{1}{y} d y = ln (∣ y ∣)

= \frac{1}{4} ln ∣ y ∣

Add a constant to the solution

= \frac{1}{4} ln ∣ y ∣ + C

\int cos^{4} (5 x) sin (5 x) d x

\int \frac{1}{441 - 400 x ^{2}} d x

\frac{d}{d x} (\frac{1}{3} \cdot (x^{2} + 2)^{\frac{3}{2}})

x^{3} - 6 x^{2} + 8 x, x^{2} - 4 x

t^{4} y^{^{''}} + t^{3} y^{^{'}} = 0