What is inverse oflaplace 1/(x-1) ?

The answer to inverse oflaplace 1/(x-1) is e^t

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inverse oflaplace 1/(x-1)

inverse laplace

\frac{1}{x - 1}

e^{t}

Solution steps

L^{- 1} {\frac{1}{x - 1}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{x - 1}} = e^{t}

= e^{t}

\frac{d}{d x} (x^{π^{2}} + (π^{2})^{x})

\frac{d}{d x} (\frac{sin ( 2 x )}{cos ( 2 x )})

\frac{d}{d x} (e^{x - 1} - x + 1)

f (x) = x^{8} e^{x}

x y^{^{'}} + y = e^{x}, y (1) = 5

What is inverse oflaplace 1/(x-1) ?
The answer to inverse oflaplace 1/(x-1) is e^t