What is area y=sqrt(x),y=sqrt(x+6),0<x<5 ?

The answer to area y=sqrt(x),y=sqrt(x+6),0<x<5 is -4sqrt(6)+(-10sqrt(5)+22sqrt(11))/3

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area y=sqrt(x),y=sqrt(x+6),0<x<5

area

y = x, y = x + 6, 0 < x < 5

- 46 + \frac{- 10 5 + 22 11}{3}

Decimal Notation

7.07039 \dots

Solution steps

Apply the area formula:

\int_{0}^{5} x - x + 6 d x

Solve

\int_{0}^{5} x - x + 6 d x : - 46 + \frac{- 10 5 + 22 11}{3}

The area is:

= - 46 + \frac{- 10 5 + 22 11}{3}

\int_{- \frac{1}{3}}^{\frac{1}{3}} \frac{1}{( 1 - x ^{2} )} d x

\frac{\partial}{\partial y} (- \frac{y}{x})

\int_{0}^{\frac{π}{3}} cos (\frac{2 x}{3}) d x

x^{2} + 5 x + 1, x^{3} + x^{2} + x + 1

\int \frac{1}{( x - 2 ) ^{3}} d x

What is area y=sqrt(x),y=sqrt(x+6),0<x<5 ?
The answer to area y=sqrt(x),y=sqrt(x+6),0<x<5 is -4sqrt(6)+(-10sqrt(5)+22sqrt(11))/3