What is the solution for y^3dx=2x^3dy-2x^2ydx ?

The solution for y^3dx=2x^3dy-2x^2ydx is y= x/(sqrt(-ln(x)+c_{1))},y=-x/(sqrt(-ln(x)+c_{1))}

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y^3dx=2x^3dy-2x^2ydx

y^{3} d x = 2 x^{3} d y - 2 x^{2} y d x

y = \frac{x}{- ln ( x ) + c _{1}}, y = - \frac{x}{- ln ( x ) + c _{1}}

Solution steps

y^{3} d x = 2 x^{3} d y - 2 x^{2} y d x

Solve Bernoulli ODE:

y = \frac{x}{- ln ( x ) + c _{1}}, y = - \frac{x}{- ln ( x ) + c _{1}}

y = \frac{x}{- ln ( x ) + c _{1}}, y = - \frac{x}{- ln ( x ) + c _{1}}

\int 1 + \frac{16}{9 \cdot x ^{\frac{2}{3}}} d x

\int_{0}^{7} 1 + 9 x d x

6 y^{^{'''}} + 3 y^{^{''}} = 0

\frac{3}{( x + 6 )}, at x = - 4

\frac{s}{s ^{2} - 2}

What is the solution for y^3dx=2x^3dy-2x^2ydx ?
The solution for y^3dx=2x^3dy-2x^2ydx is y= x/(sqrt(-ln(x)+c_{1))},y=-x/(sqrt(-ln(x)+c_{1))}