What is the solution for 6y^{'''}+3y^{''}=0 ?

The solution for 6y^{'''}+3y^{''}=0 is y=c_{1}e^{-t/2}+c_{2}+c_{3}t

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6y^{'''}+3y^{''}=0

6 y^{^{'''}} + 3 y^{^{''}} = 0

y = c_{1} e^{- \frac{t}{2}} + c_{2} + c_{3} t

Solution steps

6 y^{'''} (t) + 3 y^{''} (t) = 0

Solve linear ODE:

y = c_{1} e^{- \frac{t}{2}} + c_{2} + c_{3} t

y = c_{1} e^{- \frac{t}{2}} + c_{2} + c_{3} t

\frac{3}{( x + 6 )}, at x = - 4

\frac{s}{s ^{2} - 2}

y^{^{'}} = 7 x + y

\frac{d y}{d x} + 3 x y^{2} = 0, y (0) = 1

\frac{d}{d x} ((\frac{6 x ^{2}}{4 - x})^{3})

What is the solution for 6y^{'''}+3y^{''}=0 ?
The solution for 6y^{'''}+3y^{''}=0 is y=c_{1}e^{-t/2}+c_{2}+c_{3}t