What is the tangent of 3/((x+6)),\at x=-4 ?

The tangent of 3/((x+6)),\at x=-4 is y=-3/4 x-3/2

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tangent of 3/((x+6)),\at x=-4

tangent of

\frac{3}{( x + 6 )}, at x = - 4

y = - \frac{3}{4} x - \frac{3}{2}

Solution steps

Find the tangent point:

(- 4, \frac{3}{2})

Find the slope of

y = \frac{3}{x + 6} : \frac{d y}{d x} = - \frac{3}{( x + 6 ) ^{2}}

Compute the slope of

y = \frac{3}{x + 6}

x = - 4 : m = - \frac{3}{4}

Find the line with slope m=

- \frac{3}{4}

and passing through

(- 4, \frac{3}{2}) : y = - \frac{3}{4} x - \frac{3}{2}

y = - \frac{3}{4} x - \frac{3}{2}

\frac{s}{s ^{2} - 2}

y^{^{'}} = 7 x + y

\frac{d y}{d x} + 3 x y^{2} = 0, y (0) = 1

\frac{d}{d x} ((\frac{6 x ^{2}}{4 - x})^{3})

n = 0 \sum \infty \frac{n}{n ^{4} + 1}

What is the tangent of 3/((x+6)),\at x=-4 ?
The tangent of 3/((x+6)),\at x=-4 is y=-3/4 x-3/2