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Popular >

y^'=7x+y

Solution

y^{^{'}} = 7 x + y

Solution

y = - 7 (x + 1) + c_{1} e^{x}

Solution steps

y^{'} (x) = 7 x + y

Solve linear ODE:

y = - 7 (x + 1) + c_{1} e^{x}

y = - 7 (x + 1) + c_{1} e^{x}

Popular Examples

(dy)/(dx)+3xy^2=0,y(0)=1

\frac{d y}{d x} + 3 x y^{2} = 0, y (0) = 1

derivative of ((6x^2/(4-x))^3)

\frac{d}{d x} ((\frac{6 x ^{2}}{4 - x})^{3})

sum from n=0 to infinity of n/(n^4+1)

n = 0 \sum \infty \frac{n}{n ^{4} + 1}

derivative of (x+9/(x^3+x-8))

\frac{d}{d x} (\frac{x + 9}{x ^{3} + x - 8})

integral from-1 to 3 of x/(x^2+1)

\int_{- 1}^{3} \frac{x}{x ^{2} + 1} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=7x+y ?
The solution for y^'=7x+y is y=-7(x+1)+c_{1}e^x