What is the derivative of 9x^2cos(x)cot(x) ?

The derivative of 9x^2cos(x)cot(x) is 9(2xcos(x)cot(x)+(-cos(x)-cot(x)csc(x))x^2)

What is the first derivative of 9x^2cos(x)cot(x) ?

The first derivative of 9x^2cos(x)cot(x) is 9(2xcos(x)cot(x)+(-cos(x)-cot(x)csc(x))x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

9 x^{2} cos (x) cot (x)

9 (2 x cos (x) cot (x) + (- cos (x) - cot (x) csc (x)) x^{2})

Solution steps

\frac{d}{d x} (9 x^{2} cos (x) cot (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (x^{2} cos (x) cot (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = cos (x) cot (x)

= 9 (\frac{d}{d x} (x^{2}) cos (x) cot (x) + \frac{d}{d x} (cos (x) cot (x)) x^{2})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (cos (x) cot (x)) = - cos (x) - cot (x) csc (x)

= 9 (2 x cos (x) cot (x) + (- cos (x) - cot (x) csc (x)) x^{2})

f (x) = \frac{7}{x}, (4, \frac{7}{2})

\frac{d y}{d x} - 2 y = e^{5 x}

\frac{d}{d x} (- 5 sin (2 x))

\frac{d}{d x} (cos (x + 1))

x^{2} y^{^{''}} - 4 x y^{^{'}} - 36 y = 0

What is the derivative of 9x^2cos(x)cot(x) ?
The derivative of 9x^2cos(x)cot(x) is 9(2xcos(x)cot(x)+(-cos(x)-cot(x)csc(x))x^2)
What is the first derivative of 9x^2cos(x)cot(x) ?
The first derivative of 9x^2cos(x)cot(x) is 9(2xcos(x)cot(x)+(-cos(x)-cot(x)csc(x))x^2)