What is the limit as x approaches 0 of ((x+1)^2-1)/x ?

The limit as x approaches 0 of ((x+1)^2-1)/x is 2

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limit as x approaches 0 of ((x+1)^2-1)/x

x \to 0 lim (\frac{( x + 1 ) ^{2} - 1}{x})

2

Solution steps

x \to 0 lim (\frac{( x + 1 ) ^{2} - 1}{x})

Simplify

\frac{( x + 1 ) ^{2} - 1}{x} : x + 2

= x \to 0 lim (x + 2)

Plug in the value

x = 0

= 0 + 2

Simplify

= 2

y^{^{'}} = 6 x + y, y (0) = 8

\int_{0}^{l n (2)} e^{- x} d x

\frac{d y}{d x} = \frac{sec ( y )}{( x - 1 ) ^{2}}

\int (- x^{2} - 2 x) d x

y = x, y = \frac{1}{2} x, x = 9

What is the limit as x approaches 0 of ((x+1)^2-1)/x ?
The limit as x approaches 0 of ((x+1)^2-1)/x is 2