What is the solution for y^{''}-11y^'+30y=0 ?

The solution for y^{''}-11y^'+30y=0 is y=c_{1}e^{6t}+c_{2}e^{5t}

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y^{''}-11y^'+30y=0

y^{^{''}} - 11 y^{^{'}} + 30 y = 0

y = c_{1} e^{6 t} + c_{2} e^{5 t}

Solution steps

y^{''} (t) - 11 y^{'} (t) + 30 y = 0

Solve linear ODE:

y = c_{1} e^{6 t} + c_{2} e^{5 t}

y = c_{1} e^{6 t} + c_{2} e^{5 t}

(\frac{- 2}{3}, \frac{4}{5}), (\frac{12}{5}, \frac{- 4}{9})

\frac{d}{d x} ((1 + x)^{- 1})

\frac{d}{d x} (3 x^{2} + \frac{4 x}{3} - 2)

\frac{( y ^{^{'}} - e ^{- t} + 5 )}{y} = - 5

f (x) = 9 - x

What is the solution for y^{''}-11y^'+30y=0 ?
The solution for y^{''}-11y^'+30y=0 is y=c_{1}e^{6t}+c_{2}e^{5t}