What is the (x^2-25ln(x^2))^' ?

The (x^2-25ln(x^2))^' is 2x-(50)/x

What is the first (x^2-25ln(x^2))^' ?

The first (x^2-25ln(x^2))^' is 2x-(50)/x

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(x^{2} - 25 ln (x^{2}))^{^{'}}

2 x - \frac{50}{x}

Solution steps

(x^{2} - 25 ln (x^{2}))^{'}

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= (x^{2})^{^{'}} - (25 ln (x^{2}))^{^{'}}

(x^{2})^{'} = 2 x

(25 ln (x^{2}))^{'} = \frac{50}{x}

= 2 x - \frac{50}{x}

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