What is (\partial)/(\partial x)(x-1) ?

The answer to (\partial)/(\partial x)(x-1) is 1

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(\partial)/(\partial x)(x-1)

\frac{\partial}{\partial x} (x - 1)

1

Solution steps

\frac{\partial}{\partial x} (x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (1) = 0

= 1 - 0

Simplify

= 1

\frac{7}{1 + x}

\frac{\partial}{\partial x} (3 x^{2} y - 1)

\int \frac{6 x + 2}{x ^{2} + 9} d x

\frac{d}{d x} (\frac{x + 3}{x + 2})

\frac{d}{d x} (\frac{4}{4 - 10 x})

What is (\partial)/(\partial x)(x-1) ?
The answer to (\partial)/(\partial x)(x-1) is 1