What is the integral of tan(θ)sec^2(θ) ?

The integral of tan(θ)sec^2(θ) is (tan^2(θ))/2+C

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integral of tan(θ)sec^2(θ)

\int tan (θ) sec^{2} (θ) d θ

\frac{tan ^{2} ( θ )}{2} + C

Solution steps

\int tan (θ) sec^{2} (θ) d θ

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= \frac{u ^{2}}{2}

Substitute back

u = tan (θ)

= \frac{tan ^{2} ( θ )}{2}

Add a constant to the solution

= \frac{tan ^{2} ( θ )}{2} + C

\frac{d}{d x} (\frac{x ^{2} - 2}{2 x + 1})

\int ln (x^{2}) d x

\frac{x d y}{d x} + y = e^{- x}

9 y^{^{''}} + 6 y^{^{'}} + 6 y = 0

\int_{3}^{4} 15 x (x - 2)^{4} d x

What is the integral of tan(θ)sec^2(θ) ?
The integral of tan(θ)sec^2(θ) is (tan^2(θ))/2+C